Laura Rossouw vs Jane Fitzalan Howard Head to Head Stats

Wojtek Kolan

Our Predictions

H2H Records Career Stats

HEAD TO HEAD
L. Rossouw vs J. Fitzalan Howard

Laura Rossouw

RSA

1

Win

Played

0

Win

Age

Height

Ret.

C. Rank

Ret.

Best Rank

Total Titles

YTD Titles

Career Money

Plays

Jane Fitzalan Howard

GBR

1

Win

Played

0

Win

Age

Height

Ret.

C. Rank

Ret.

Best Rank

Total Titles

YTD Titles

Career Money

Plays

Head-to-head: Rossouw 1 - 0 Howard

They have played 2 sets in total, with Laura Rossouw winning 2 and Jane Fitzalan Howard winning 0. The last match between Laura Rossouw and Jane Fitzalan Howard was at the Guildford, 08-05-1967, Round: R3, Surface: Clay, with Laura Rossouw getting the victory 6-1 6-3.

Players	Head To Head Match Wins
Rossouw	1
Howard	0

Last 1 H2H Matches:

(R3) Guildford(05-08-67)

Stats

Laura Rossouw

Jane Fitzalan Howard

L. Rossouw vs J. F. Howard H2H Profile

L. Rossouw	Stats	J. F. Howard
$0	Career Prize Money	$0
50.14% (176-175)	Career Total W/L	21.05% (4-15)
1	Clay	0
1	Total H2H Matches	0
0% (0-0)	YTD Win/Loss	0% (0-0)

L. Rossouw vs J. F. Howard Match Preview:

Second serve performance recent form: In recent form (last 6 months), Laura Rossouw has won 0% of points on their second serve, while Jane Fitzalan Howard has won 0%. There is a high correlation between this stat and match prediction accuracy.
Return game stats recent form: Return stats show Laura Rossouw, in recent form, has won 0% of their opponent's second serve points, while Jane Fitzalan Howard has won 0%. The same stats for first serve returns are 0% and 0% respectively and this has a high correlation to pick who is favored in this H2H matchup.
Under pressure analysis: Laura Rossouw has saved 0% of breakpoints in recent form, whereas Jane Fitzalan Howard has saved 0% which is a useful statistic for in-game betting predictions.
Performance overview: Over the last year Laura Rossouw has won 0% of matches played (W/L 0/0), with Jane Fitzalan Howard winning 0% (W/L 0/0) that gives us an overall head-to head prediction overview.
Best surface: Laura Rossouw has their best career surface win % on Grass, winning 60% (W/L 45/30), and worse career win % on Hard, winning 44% (W/L 28/36). Jane Fitzalan Howard has their best career surface win % on Clay, winning 60% (W/L 4/15), and worse career win % on Clay, winning 21% (W/L 4/15).
Player level: In the last year, Laura Rossouw has played most of their matches on the N/A, winning 0% of matches (W/L 0/0), where as Jane Fitzalan Howard has played most of their matches on the N/A, winning 0% of matches (W/L 0/0). When comparing stats between players to predict the favorite, it is of course all relative to the event level they have been playing at.
Direct H2H matches: They have played 1 times before with Laura Rossouw winning 1 times and Jane Fitzalan Howard being victorious 0 times. They have played 2 sets in total, with Laura Rossouw winning 2 and Jane Fitzalan Howard winning 0.
The last match between Laura Rossouw and Jane Fitzalan Howard was at the Guildford, 08-05-1967, Round: R3, Surface: Clay, with Laura Rossouw getting the victory 6-1 6-3.
Head to head match duration: In past head to head matches, the average match time between these players has been 0:0:0.
Opponent quality stats: Over the last 12 months, Laura Rossouw has played against opponents with an average rank of 0 while Jane Fitzalan Howard has played against players with an average rank of 0.
Deciding set performance vs all players: If you are interested in live predictions and betting, if this match goes into a deciding set, Laura Rossouw has won 0% of deciding sets over the last 12 months, while Jane Fitzalan Howard has won 0% in all matches played on tour.
Break point conversion: In recent form, Laura Rossouw has converted 0% of breakpoint opportunities, and Jane Fitzalan Howard has converted 0% of their chances to break their opponents serve. A telling stat for in-game live betting tips when either player has a breakpoint opportunity.

Laura Rossouw vs Jane Fitzalan Howard Editorial Preview By TennisTipster88.

L. Rossouw vs J. F. Howard H2H Stats Used In Our Predictions

L. Rossouw	Stats	J. F. Howard
1	H2H Matches Won	0
2	Sets Won	0
12	Games Won	4
0:0:0	Average Match Time	0:0:0
100% (1/1)	Best‑of‑3 Win %	0% (0/1)
100% (1/1)	1st Set Won, Won Match	0% (0/0)
0% (0/1)	1st Set Won, Lost Match	0% (0/0)
0% (0/0)	1st Set Lost, Won Match	0% (0/1)

Recent Performance Stats

L. Rossouw Recent Matches Played

OPPONENT	RESULT	SCORE	H2H
ITF Pretoria - 27-02-1989
R4 Pye MoretonP. Moreton	L	6-0 6-0	Stats
R3 Denise ParnellD. Parnell	W	6-0 6-3	Stats
ITF Bloemfontein - 20-02-1989
R3 Janine HumphreysJ. Humphreys	L	1-6 7-6(4) 6-2	Stats
Unknown Tournament - 12-08-1974
R3 Kazuko SawamatsuK. Sawamatsu	L	6-3 6-2	Stats
Unknown Tournament - 24-06-1974
R2 Karen KrantzckeK. Krantzcke	L	6-0 6-3	Stats

View All

J. F. Howard Recent Matches Played

OPPONENT	RESULT	SCORE	H2H
Hurlingham - 12-05-1969
R3 Christine TrumanC. Truman	L	6-1 6-2	Stats
Guildford - 05-05-1969
R2 Christiane SpinozaC. Spinoza	L	6-2 6-1	Stats
Hampstead - 21-04-1969
R3 Sandra OkinS. Okin	L	6-3 6-0	Stats
Guildford - 06-05-1968
R3 Judy CongdonJ. Congdon	L	6-4 6-2	Stats
R2 Vivian GrisogonoV. Grisogono	W	6-2 6-2	Stats

View All

L. Rossouw vs J. F. Howard Stats Breakdown Vs All H2H Opponents

L. Rossouw	Stats	J. F. Howard
50.14% (176/175)	YTD Win/Loss	21.05% (4/15)
49.10% (384/398)	Sets Win/Loss	25.00% (10/30)
100.00% (3584/0)	Games Win/Loss	38.70% (125/198)
43.75% (28/36)	Hard Win/Loss	0% (0/0)
51.64% (63/59)	Clay Win/Loss	21.05% (4/15)
40.00% (6/9)	Indoor Hard W/L	0% (0/0)
60.00% (45/30)	Grass Win/Loss	0% (0/0)
1st Match	Average Match Time	1st Match
12.06	Average Opponent Rank	0
47.06% (8/9)	Slam W/L	0% (0/0)
100.00% (2/0)	Cups W/L	0% (0/0)
33.33% (1/2)	Challenger W/L	0% (0/0)
45.59% (31/37)	Futures W/L	0% (0/0)
50% (169/341)	Best of 3 Sets Win %	21% (4/19)
40% (2/5)	Tiebreaks Win % (Total)	0% (0/0)
55% (52/94)	Deciding Set Win %	0% (0/2)
85% (165/141)	1st Set Won, Won Match	80% (5/4)
15% (165/24)	1st Set Won, Lost Match	20% (5/1)
17% (181/31)	1st Set Lost, Won Match	0% (14/0)